A machine gun is fired at a steel plate. Is the average force on the plate from the bullet impact greater if the bullets bounce off or if they are squashed and stick to the plate? Explain.
Solution 14DQ Step 1 of 3: From newton's second law, we know that; net force on the particle is equal to the rate of change of momentum. That is F= dt Where F is the net force and P is the momentum. Step 2 of 3: In the given problem, let P be the initial momentum When the bullets are bounced back from the plate, Change in momentum is, F = dP bounce dt Fbounce= P-(-P)= 2P Similarly when the bullets are squashed from the plate its speed decrease, dP Change in momentum is, Fsquashed dt Fsquashed P-P 1 Similarly when the bullets stick the plate its final speed drops to zero resulting momentum to zero, Change in momentum is, F = dP stick dt Fstick P-0= P
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 14DQ from 8 chapter was answered, more than 716 students have viewed the full step-by-step answer. The answer to “A machine gun is fired at a steel plate. Is the average force on the plate from the bullet impact greater if the bullets bounce off or if they are squashed and stick to the plate? Explain.” is broken down into a number of easy to follow steps, and 37 words. This full solution covers the following key subjects: plate, Greater, bullet, BUllets, explain. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The full step-by-step solution to problem: 14DQ from chapter: 8 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13.