A 0.150-kg glider is moving to the right with a speed of 0.80 m/s on a frictionless, horizontal air track. The glider has a head-on collision with a 0.300-kg glider that is moving to the left with a speed of 2.20 m/s. Find the final velocity (magnitude and direction) of each glider if the collision is elastic.

Solution 46E Step 1: Mass of glider moving right m 1 = 0.150 Kg Mass of glider moving left m 2 = 0.300 Kg Initial Velocity of glider moving right u = 0.80 m/s (+x direction) 1 Initial Velocity of glider moving left u 2 = - 2.2 m/s (-x direction) Step 2: The gliders collide and momentum is conserved. After collision the gliders move in the direction of the glider which collides left. Because mass and velocity of that glider are greater. Total momentum before collision is equal to the total momentum after collision. m 1 1 u2 2 v +1 1 ---2 2 Let final velocities of the gliders after collision be v and v 1 2 Step 3: Applying all known values 0.15x0.8 + 0.3x(-2.2) = 0.15v +0.3v 1 2 Step 4 : Simplifying -0.54 = 0.15v +0.3v 1 2 15v 130v = -2 v12v 2-3.6 m/s ------(2)