Three odd-shaped blocks of chocolate have the following masses and center-of-mass coordinates: (1) 0.300 kg, (0.200 m,0.300 m); (2) 0.400 kg, (0.100 m, - 0.400 m); (3) 0.200 kg, (-0.300 m, 0.600 m). Find the coordinates of the center of mass of the system of three chocolate blocks.

Solution 51E Step 1: Mass of the block of chocolate at point 1, m = 0.300 kg 1 Coordinates of block of chocolate at point 1, P = (0.200 m, 0.300 m1= (x ,y ) 1 1 X- component of point 1, x = 0.200 m 1 Y- component of point 1, y = 0.300 m 1 Mass of the block of chocolate at point 2, m = 0.400 kg 2 Coordinates of block of chocolate at point 2, P = (0.100 m, -0.400 m) = (x ,y ) 2 2 2 X- component of point 2, x = 0.100 m 2 Y- component of point 2, y = -0.400 m 2 Mass of the block of chocolate at point 3, m = 0.200 kg 3 Coordinates of block of chocolate at point 3, P = (-0.300 m, 0.600 3 = (x ,y ) 3 3 X- component of point 3, x = -0.300 m 3 Y- component of point 3, y = 0.600 m 3