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A steel ball with mass 40.0 g is dropped from a height of

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 67P Chapter 8

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 67P

A steel ball with mass 40.0 g is dropped from a height of 2.00 m onto a horizontal steel slab. The ball rebounds to a height of 1.60 m. (a) Calculate the impulse delivered to the ball during impact. (b) If the ball is in contact with the slab for 2.00 ms, find the average force on the ball during impact.

Step-by-Step Solution:
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Solution 67P To solve this question, we shall have to take into account the equation of motion v = u + 2gh…..(1) , where v is the final velocity, u is the initial velocity and h is the height from which the ball is dropped. Moreover, we shall have to use the relation impulse = change in momentum and impulse = force × time. Given, h = 2.00 m Initial speed u = 0 Therefore, from equation 1, v = 0 + 2 × g × 2.00 m v = 2 × 9.80 m/s × 2.00 m v = 6.3 m/s The ball rebounds to a height of 1.60 m. So, final velocity at the maximum height is 0. Let u be1the initial speed. 2 2 Therefore, 0 = u 1 2 × 9.80 m/s × 1.60 m u 1 5.6 m/s Since the...

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Chapter 8, Problem 67P is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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