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CP Two identical masses are released from rest in a smooth

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 86P Chapter 8

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 86P

CP? Two identical masses are released from rest in a smooth hemispherical bowl of radius R from the positions shown in ?Fig. P8.82.? Ignore friction between the masses and the surface of the bowl. If the masses stick together when they collide, how high above the bottom of the bowl will they go after colliding?

Step-by-Step Solution:

Solution 86 P Step 1: Let us consider the figure given From this we can notice that one block is at the top of left side of arc while the other is at the center We shall find the energy required by the one block to collide with other Energy of block one E1= mgR-----------(1) Velocity of block of B is B 2 And v B 1/2 mv B ---------(2) Using (1) and (2) We get v = 2gR B After the collision linear momentum is conserved Hence the velocity of the system after collision will be v = 2gR = mv B 2mv A Hence we get velocity of particle A as vA= v B2 Substitute forB= 2gR We get vA= gR/2 Velocity of particle after collision will be 2 = 1/2 2mv A This can further written as = 2mg y (y = change in position along y axis ) To find the position of the block after collision y = v A2g But we have vA= gR/2 Hence we can write as y = gR/2g × 2 Simplifying this get y = R/4 Hence we get the position of the block after the collision as R/4

Step 2 of 1

Chapter 8, Problem 86P is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

This full solution covers the following key subjects: Masses, bowl, bottom, colliding, fig. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The answer to “CP? Two identical masses are released from rest in a smooth hemispherical bowl of radius R from the positions shown in ?Fig. P8.82.? Ignore friction between the masses and the surface of the bowl. If the masses stick together when they collide, how high above the bottom of the bowl will they go after colliding?” is broken down into a number of easy to follow steps, and 55 words. This textbook survival guide was created for the textbook: University Physics, edition: 13. Since the solution to 86P from 8 chapter was answered, more than 451 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 86P from chapter: 8 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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CP Two identical masses are released from rest in a smooth