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CP In a shipping company distribution center, an open cart

Chapter 10, Problem 95P

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QUESTION:

CP? In a shipping company distribution center, an open cart of mass 50.0 kg is rolling to the left at a speed of 5.00 m/s (?Fig. P8.87?). Ignore friction between the cart and the floor. A 15.0-kg package slides down a chute that is inclined at 37o from the horizontal and leaves the end of the chute with a speed of 3.00 m/s. The package lands in the cart and they roll together. If the lower end of the chute is a vertical distance of 4.00 m above the bottom of the cart, what are (a) the speed of the package just before it lands in the cart and (b) the final speed of the cart?

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QUESTION:

CP? In a shipping company distribution center, an open cart of mass 50.0 kg is rolling to the left at a speed of 5.00 m/s (?Fig. P8.87?). Ignore friction between the cart and the floor. A 15.0-kg package slides down a chute that is inclined at 37o from the horizontal and leaves the end of the chute with a speed of 3.00 m/s. The package lands in the cart and they roll together. If the lower end of the chute is a vertical distance of 4.00 m above the bottom of the cart, what are (a) the speed of the package just before it lands in the cart and (b) the final speed of the cart?

ANSWER:

Solution 95P This question can be solved considering the equations of conservation of energy and momentum. Given, mass of the package m = 15p0 kg Speed of the package v = 3p00 m/s Height of the chute above the bottom of the cart h = 4.00 m Let v b1 the speed of the package when it lands in the cart. Therefore, using the principle of conservation of energy, (a) Total initial energy = Total final energy

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