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Solved: Calculate the mass of each of the following: (a) a

Chemistry | 11th Edition | ISBN: 9780073402680 | Authors: Raymond Chang ISBN: 9780073402680 118

Solution for problem 57P Chapter 1

Chemistry | 11th Edition

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Chemistry | 11th Edition | ISBN: 9780073402680 | Authors: Raymond Chang

Chemistry | 11th Edition

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Problem 57P

Calculate the mass of each of the following: (a) a sphere of gold with a radius of 10.0 cm [the volume of a sphere with a radius r is \(V=(4 / 3) \pi r^{3}\); the density of gold = \(19.3\mathrm{\ g}/\mathrm{cm}^3\)], (b) a cube of platinum of edge length 0.040 mm (the density of platinum = \(21.4\mathrm{\ g}/\mathrm{cm}^3\)), (c) 50.0 mL of ethanol (the density of ethanol = 0.798 g/mL).

Step-by-Step Solution:

Step 1 of 3

Here we have to calculate the mass.

It is known that mass = density  volume

 (a)  a sphere of gold with a radius of 10.0 cm

In this question it has been given that,

 where r is the radius = 10.0 cm

               

             

Mass = density volume

         

         

Thus the mass of the gold sphere is found to be

 

Step 2 of 3

Chapter 1, Problem 57P is Solved
Step 3 of 3

Textbook: Chemistry
Edition: 11
Author: Raymond Chang
ISBN: 9780073402680

Chemistry was written by and is associated to the ISBN: 9780073402680. This full solution covers the following key subjects: Density, platinum, sphere, gold, ethanol. This expansive textbook survival guide covers 25 chapters, and 3591 solutions. The answer to “?Calculate the mass of each of the following: (a) a sphere of gold with a radius of 10.0 cm [the volume of a sphere with a radius r is \(V=(4 / 3) \pi r^{3}\); the density of gold = \(19.3\mathrm{\ g}/\mathrm{cm}^3\)], (b) a cube of platinum of edge length 0.040 mm (the density of platinum = \(21.4\mathrm{\ g}/\mathrm{cm}^3\)), (c) 50.0 mL of ethanol (the density of ethanol = 0.798 g/mL).” is broken down into a number of easy to follow steps, and 70 words. This textbook survival guide was created for the textbook: Chemistry, edition: 11. Since the solution to 57P from 1 chapter was answered, more than 9826 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 57P from chapter: 1 was answered by , our top Chemistry solution expert on 11/08/17, 03:59AM.

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