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Solved: On p. 40 it was pointed out that mass and energy

Chapter 2, Problem 104P

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QUESTION:

On p. 40 it was pointed out that mass and energy are alternate aspects of a single entity called mass-energy. The relationship between these two physical quantities is Einstein's famous equation, \(E=m c^{2}\), where \(E\) is energy, \(m\) is mass, and \(c\) is the speed of light. In a combustion experiment, it was found that 12.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form water and released \(1.715\times10^3\mathrm{\ kJ}\) of heat. Calculate the corresponding mass change in this process and comment on whether the law of conservation of mass holds for ordinary chemical processes. (Hint: The Einstein equation can be used to calculate the change in mass as a result of the change in energy. \(1\mathrm{\ J}=1\mathrm{\ kg}\mathrm{\ m}^2/\mathrm{s}^2\) and \(c=3.00\times10^8\mathrm{\ m}/\mathrm{s}\).)

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QUESTION:

On p. 40 it was pointed out that mass and energy are alternate aspects of a single entity called mass-energy. The relationship between these two physical quantities is Einstein's famous equation, \(E=m c^{2}\), where \(E\) is energy, \(m\) is mass, and \(c\) is the speed of light. In a combustion experiment, it was found that 12.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form water and released \(1.715\times10^3\mathrm{\ kJ}\) of heat. Calculate the corresponding mass change in this process and comment on whether the law of conservation of mass holds for ordinary chemical processes. (Hint: The Einstein equation can be used to calculate the change in mass as a result of the change in energy. \(1\mathrm{\ J}=1\mathrm{\ kg}\mathrm{\ m}^2/\mathrm{s}^2\) and \(c=3.00\times10^8\mathrm{\ m}/\mathrm{s}\).)

ANSWER:

Step 1 of 3

Here we have to calculate the change in mass using Einstein equation in the combustion experiment.

 

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