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Solved: Fermentation is a complex chemical process of wine
Chapter 3, Problem 72P(choose chapter or problem)
Fermentation is a complex chemical process of wine making in which glucose is converted into ethanol and carbon dioxide:
\(\underset{\text { glucose }}{\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}} \longrightarrow \underset{\text { ethanol }}{2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}}+2 \mathrm{CO}_{2}\)
Starting with 500.4 g of glucose, what is the maximum amount of ethanol in grams and in liters that can be obtained by this process? (Density of ethanol = 0.789 g/mL.)
Questions & Answers
QUESTION:
Fermentation is a complex chemical process of wine making in which glucose is converted into ethanol and carbon dioxide:
\(\underset{\text { glucose }}{\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}} \longrightarrow \underset{\text { ethanol }}{2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}}+2 \mathrm{CO}_{2}\)
Starting with 500.4 g of glucose, what is the maximum amount of ethanol in grams and in liters that can be obtained by this process? (Density of ethanol = 0.789 g/mL.)
ANSWER:
Step 1 of 3
Here we have to calculate the maximum amount of ethanol in grams and in liters that can be obtained by the given fermentation process.
The given reaction for fomentation is given below,
(Glucose) (ethyl alcohol)
Calculation of ethanol in gram:
Given mass of glucose = 500.4 g