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The equation for the metabolic breakdown of glucose

Chapter 5, Problem 12PE

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QUESTION:

The equation for the metabolic breakdown of glucose (\(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\)) is the same as the equation for the combustion of glucose in air:

\(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{s})+6 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)

Calculate the volume of \(\mathrm{CO}_{2}\) produced at 37℃ and 1.00 atm when 5.60 g of glucose is used up in the reaction.

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QUESTION:

The equation for the metabolic breakdown of glucose (\(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\)) is the same as the equation for the combustion of glucose in air:

\(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{s})+6 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)

Calculate the volume of \(\mathrm{CO}_{2}\) produced at 37℃ and 1.00 atm when 5.60 g of glucose is used up in the reaction.

ANSWER:

Step 1 of 2

Here we have to calculate the volume of .

 

In this question it has been given that,

The equation for the metabolic breakdown of glucose () is the same as the equation for the combustion of glucose in air:

The given equation is,

     

Temperature (T) = 37°C = 273 + 37 = 310 K

Pressure (P) = 1.00 atm

Given mass of glucose = 5.60 g

 

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