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Solved: A gaseous hydrocarbon (containing C and H atoms)

Chapter 5, Problem 167P

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QUESTION:

A gaseous hydrocarbon (containing C and H atoms) in a container of volume 20.2 L at 350 K and 6.63 atm reacts with an excess of oxygen to form 205.1 g of \(\mathrm{CO}_{2}\) and 168.0 g of \(\mathrm{H}_{2} \mathrm{O}\). What is the molecular formula of the hydrocarbon?

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QUESTION:

A gaseous hydrocarbon (containing C and H atoms) in a container of volume 20.2 L at 350 K and 6.63 atm reacts with an excess of oxygen to form 205.1 g of \(\mathrm{CO}_{2}\) and 168.0 g of \(\mathrm{H}_{2} \mathrm{O}\). What is the molecular formula of the hydrocarbon?

ANSWER:

Step 1 of 3

Here we have to find out the molecular formula of the hydrocarbon.

 

Given:

Volume of the container = 20.2 L

Temperature = 350 K

Pressure = 6.63 atm

Mass of   = 205.1 g

Mass of  = 168.0 g

Molecular mass of  = 44.01 g

Molecular mass of  = 18.02 g

 

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