An electric turntable 0.750 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.250 rev/s and a constant angular acceleration of 0.900 rev/s2. (a) Compute the angular velocity of the turntable after 0.200 s. (b) Through how many revolutions has the turntable spun in this time interval? (c) What is the tangential speed of a point on the rim of the turn-table at t = 0.200 s? (d) What is the magnitude of the ?resultant? acceleration of a point on the rim at t = 0.200 s?

Solution 24E Diameter of the turntable is, D = 0.750 m. The radius will be, r = 0.750 / 2 = 0.375 m. Initial angular velocity was, = 0.250 rev/s. 0 2 Angular acceleration is, = 0.900 rev/s . a)Angular velocity after 0.200 s will be, = + t = 0.250 + 0.900 × 0.200 = 0.43 rev/s. 0 b)I n 0.200 s the number of revolutions will be, = t + t = 0.250 × 0.200 + 0.5 × 0.900 × 0.200 = 0.068 revolutions. 0 2 c)The tangential speed...