Mass of Fluorine in 24.6g SnF? Toothpaste: A Breakdown

Step 1 of 2

Here, we are going to calculate the mass of F in the compound.

Given that,

Mass of the \(S n F_{2}=24.6 \mathrm{~g}\)

The molar mass of \(S n F_{2}=156.7 \mathrm{~g} / \mathrm{mol}\)

Thus, 1.0 mol of \(\mathrm{SnF}_{2}\) contains 156.7 g

Similarly,

The molar mass of  F  = 19.00 g/mol

Therefore,

\(\% \text { of } \mathrm{F} \text { by mass }=\frac{2 \times 19.00 \mathrm{~g} / \mathrm{mol}}{156.7 \mathrm{~g} / \mathrm{mol}} \times 100 \%=24.25 \%\)

Thus, the mass of F in the compound = 0.2425 g

Therefore,

The mass of F in g in the \(\mathrm{SnF}_{2}\) is \(=(24.6 \times 0.2425) \mathrm{g}\)

= 5.97 g

Therefore,the mass of F in g in the \(\mathrm{SnF}_{2}\) is 5.97 g.