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Find the moment of inertia of a hoop (a thin-walled,

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 54E Chapter 9

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 54E

Find the moment of inertia of a hoop (a thin-walled, hollow ring) with mass ?M and radius ?R? about an axis perpendicular to the hoop’s plane at an edge.

Step-by-Step Solution:

Solution 54E Step 1: The moment of inertia of the hoop about the axis passing through it’s centre which is parallel to the plane of the hoop is, 2 Iz= mr . By perpendicular axis theorem, Iz= I x I .y Where I , IxandyI are tze respective moment of inertias along the three perpendicular axes. But by symmetry, I = I x y So, I = 2I z x 1 I =xI /2z= mr .2 2

Step 2 of 2

Chapter 9, Problem 54E is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Find the moment of inertia of a hoop (a thin-walled,

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