Step 1 of 3
Here, we are asked to calculate the number of cations and anions in the given compounds
(a) Given: 0.764 g of \(CsI\)
First, let’s find the number of moles of \(CsI\):
Molar mass of CsI (Caesium iodide) = 259.81 g/mol
We know 1 mole of any unit contains Avogadro’s number of particles. Here, 1 mole of the \(CsI\) element contains Avogadro’s number of ions, .
Therefore, number of ions will be:
Cs (Caesium) is a metal and hence these ions are the cations. Hence, there are ions.
The compound, \(CsI\) contains 1 atom of Cs and 1 atom of I (Iodine). A compound always contains an equal number of cations and anions in the neutral state. Hence, \(CsI\) has anions, i.e ions.