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Solved: Calculate the number of cations and anions in each
Chapter 3, Problem 121P(choose chapter or problem)
Questions & Answers
QUESTION:
Calculate the number of cations and anions in each of the following compounds:
(a) \(0.764 g\) of \(CsI\),
(b) \(72.8\ \text{g}\ K_2Cr_2O_7\),
(c) \(6.54\ \text{g}\ \text{of}\ Hg_2(NO_3)_2\).
ANSWER:Step 1 of 3
Here, we are asked to calculate the number of cations and anions in the given compounds
(a) Given: 0.764 g of \(CsI\)
First, let’s find the number of moles of \(CsI\):
Molar mass of CsI (Caesium iodide) = 259.81 g/mol
We know 1 mole of any unit contains Avogadro’s number of particles. Here, 1 mole of the \(CsI\) element contains Avogadro’s number of ions, 
Therefore, number of ions will be:
=
= 
Cs (Caesium) is a metal and hence these ions are the cations. Hence, there are 
The compound, \(CsI\) contains 1 atom of Cs and 1 atom of I (Iodine). A compound always contains an equal number of cations and anions in the neutral state. Hence, \(CsI\) has 
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