Solution Found!
Solved: The wave function for the 2s orbital in the
Chapter 7, Problem 152P(choose chapter or problem)
The wave function for the 2s orbital in the hydrogen atom is
\(\psi_{2 s}=\frac{1}{\sqrt{2 a_{0}^{3}}}\left(1-\frac{\rho}{2}\right) e^{-\rho / 2}\)
where \(a_0\) is the value of the radius of the first Bohr orbit, equal to 0.529 nm, \(\rho\) is \(Z(r/a_0)\), and r is the distance from the nucleus in meters. Calculate the location of the node of the 2s wave function from the nucleus.
Questions & Answers
QUESTION:
The wave function for the 2s orbital in the hydrogen atom is
\(\psi_{2 s}=\frac{1}{\sqrt{2 a_{0}^{3}}}\left(1-\frac{\rho}{2}\right) e^{-\rho / 2}\)
where \(a_0\) is the value of the radius of the first Bohr orbit, equal to 0.529 nm, \(\rho\) is \(Z(r/a_0)\), and r is the distance from the nucleus in meters. Calculate the location of the node of the 2s wave function from the nucleus.
ANSWER:Step 1 of 2
The wave function is zero at a node, indicating that the possibilities of obtaining an electron from the nucleus are zero.
