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Plasma is a state of matter consisting of positive '
Chapter 8, Problem 58P(choose chapter or problem)
Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state a mercury atom could be stripped of its 80 electrons and therefore would exist as \(\mathrm{Hg}^{80+}\). Use the equation in Problem 8.57 to calculate the energy required for the last ionization step, that is,
\(\mathrm{Hg}^{79+}(g) \longrightarrow \mathrm{Hg}^{80+}(g)+e^{-}\)
Questions & Answers
QUESTION:
Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state a mercury atom could be stripped of its 80 electrons and therefore would exist as \(\mathrm{Hg}^{80+}\). Use the equation in Problem 8.57 to calculate the energy required for the last ionization step, that is,
\(\mathrm{Hg}^{79+}(g) \longrightarrow \mathrm{Hg}^{80+}(g)+e^{-}\)
ANSWER:Step 1 of 2
The ionization reaction is shown below.
is isoelectronic of hydrogen (atomic number=80, electron=1)