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The rate constant of a first-order reaction is 4.60 × 10

Chapter 13, Problem 42P

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QUESTION:

The rate constant of a first-order reaction is \(4.60 \times 10^{-4} s^{-1}\) at 350°C. If the activation energy is 104 kJ/mol, calculate the temperature at which its rate constant is \(8.80 \times 10^{-4} s^{-1}\).

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QUESTION:

The rate constant of a first-order reaction is \(4.60 \times 10^{-4} s^{-1}\) at 350°C. If the activation energy is 104 kJ/mol, calculate the temperature at which its rate constant is \(8.80 \times 10^{-4} s^{-1}\).

ANSWER:

Step 1 of 5

Consider the following formula:

        

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