Solution Found!
The rate law for the reaction is given by rate = . (a)
Chapter 13, Problem 55P(choose chapter or problem)
The rate law for the reaction
\(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g})\)
is given by rate = \(k[\mathrm{NO}]\left[\mathrm{Cl}_{2}\right]\). (a) What is the order of the reaction? (b) A mechanism involving the following steps has been proposed for the reaction:
\(\mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(g) \rightarrow \mathrm{NOCl}_{2}(g)\)
\(\mathrm{NOCl}_{2}(g)+\mathrm{NO}(\mathrm{g}) \rightarrow 2 \mathrm{NOCl}(g)\)
If this mechanism is correct, what does it imply about the relative rates of these two steps?
Questions & Answers
QUESTION:
The rate law for the reaction
\(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g})\)
is given by rate = \(k[\mathrm{NO}]\left[\mathrm{Cl}_{2}\right]\). (a) What is the order of the reaction? (b) A mechanism involving the following steps has been proposed for the reaction:
\(\mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(g) \rightarrow \mathrm{NOCl}_{2}(g)\)
\(\mathrm{NOCl}_{2}(g)+\mathrm{NO}(\mathrm{g}) \rightarrow 2 \mathrm{NOCl}(g)\)
If this mechanism is correct, what does it imply about the relative rates of these two steps?
ANSWER:
Step 1 of 3
We need to find the order of the given reaction first.
Order of a reaction is the relationship between rate of the reaction and concentration of molecules take part in it.
