Solution Found!
The activation energy (Ea) for the reaction is 240 kJ/mol.
Chapter 13, Problem 134P(choose chapter or problem)
QUESTION:
The activation energy (E) for the reaction
\(2 \mathrm{~N}_{2} \mathrm{O}(\mathrm{g}) \rightarrow 2 \mathrm{N}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g})\ \Delta \mathrm{H}^{\circ}=-164\ \mathrm{kJ} / \mathrm{mol}\)
is 240 kJ/mol. What is \(E_{a}\) for the reverse reaction?
Questions & Answers
QUESTION:
The activation energy (E) for the reaction
\(2 \mathrm{~N}_{2} \mathrm{O}(\mathrm{g}) \rightarrow 2 \mathrm{N}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g})\ \Delta \mathrm{H}^{\circ}=-164\ \mathrm{kJ} / \mathrm{mol}\)
is 240 kJ/mol. What is \(E_{a}\) for the reverse reaction?
ANSWER:Step 1 of 2
We have the equation
The activation energy is given by
We need to find the activation energy of the reversible reaction.