The equilibrium constant (Kc)for reaction at 80?C.If the
Chapter 14, Problem 4RC(choose chapter or problem)
The equilibrium constant \(\left(K_{c}\right)\) for reaction \(A\ \leftrightharpoons\ B+C\) is \(4.8 \times 10^{-2}\) at \(80^{\circ} \mathrm{C}\). If the forward rate constant is \(3.2 \times 10^{2}\ \mathrm{s}^{-1}\), calculate the reverse rate constant.
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