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Answer: Heating solid sodium bicarbonate in a closed
Chapter 14, Problem 54P(choose chapter or problem)
Heating solid sodium bicarbonate in a closed vessel establishes the following equilibrium:
\(2 \mathrm{NaHCO}_{3}(s)\ \leftrightharpoons\ \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}_{2}(g)\)
What would happen to the equilibrium position if (a) some of the \(\mathrm{CO}_{2}\) were removed from the system; (b) some solid \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) were added to the system; (c) some of the solid \(\mathrm{NaHCO}_{3}\) were removed from the system? The temperature remains constant.
Questions & Answers
QUESTION:
Heating solid sodium bicarbonate in a closed vessel establishes the following equilibrium:
\(2 \mathrm{NaHCO}_{3}(s)\ \leftrightharpoons\ \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}_{2}(g)\)
What would happen to the equilibrium position if (a) some of the \(\mathrm{CO}_{2}\) were removed from the system; (b) some solid \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) were added to the system; (c) some of the solid \(\mathrm{NaHCO}_{3}\) were removed from the system? The temperature remains constant.
ANSWER:Step 1 of 4
The given reaction is as follows;