Solution Found!
Answer: Consider the following equilibrium reaction in a
Chapter 14, Problem 62P(choose chapter or problem)
Consider the following equilibrium reaction in a closed container:
\(\mathrm{CaCO}_{3}(s)\ \leftrightharpoons\ \mathrm{CaO}(s)+\mathrm{CO}_{2}(g)\)
What will happen if (a) the volume is increased; (b) some CaO is added to the mixture; (c) some \(\mathrm{CaCO}_{3}\) is removed; (d) some \(\mathrm{CO}_{2}\) is added to the mixture; (e) a few drops of a NaOH solution are added to the mixture; (f) a few drops of a HCl solution are added to the mixture (ignore the reaction between \(\mathrm{CO}_{2}\) and water); (g) temperature is increased?
Questions & Answers
QUESTION:
Consider the following equilibrium reaction in a closed container:
\(\mathrm{CaCO}_{3}(s)\ \leftrightharpoons\ \mathrm{CaO}(s)+\mathrm{CO}_{2}(g)\)
What will happen if (a) the volume is increased; (b) some CaO is added to the mixture; (c) some \(\mathrm{CaCO}_{3}\) is removed; (d) some \(\mathrm{CO}_{2}\) is added to the mixture; (e) a few drops of a NaOH solution are added to the mixture; (f) a few drops of a HCl solution are added to the mixture (ignore the reaction between \(\mathrm{CO}_{2}\) and water); (g) temperature is increased?
ANSWER:Step 1 of 8
The changes made in a reversible reaction will alter the equilibrium position to subsidize the difference, and Le Chatelier's principle studied this relation.