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Get Full Access to University Physics - 13 Edition - Chapter 12 - Problem 4e
Get Full Access to University Physics - 13 Edition - Chapter 12 - Problem 4e

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# Gold Brick. You win the lottery and decide to impress your ISBN: 9780321675460 31

## Solution for problem 4E Chapter 12

University Physics | 13th Edition

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Problem 4E

Gold Brick?. You win the lottery and decide to impress your friends by exhibiting a million-dollar cube of gold. At the time, gold is selling for \$426.60 per troy ounce, and 1.0000 troy ounce equals 31.1035 g. How tall would your million-dollar cube be?

Step-by-Step Solution:

Solution 4E First we have to find the mass of the gold that has a value of one million dollar (1\$ 6 × 10 ). Then using the value of density of gold one can find the volume of this mass of gold. The 3 volume V of the cube is related to the length of one side by V = L . Step 1 of 3: 1 troy ounce 3 Mass of gold of value one million dollar = (1\$ × 10 ) ( \$426.60 )( 1 troy ounce 6 31.1035×10 = 10 × ( 426.60 ) = 72.9 kg

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321675460

This full solution covers the following key subjects: gold, dollar, ounce, Troy, million. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. Since the solution to 4E from 12 chapter was answered, more than 877 students have viewed the full step-by-step answer. The answer to “Gold Brick?. You win the lottery and decide to impress your friends by exhibiting a million-dollar cube of gold. At the time, gold is selling for \$426.60 per troy ounce, and 1.0000 troy ounce equals 31.1035 g. How tall would your million-dollar cube be?” is broken down into a number of easy to follow steps, and 44 words. The full step-by-step solution to problem: 4E from chapter: 12 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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