Gold Brick?. You win the lottery and decide to impress your friends by exhibiting a million-dollar cube of gold. At the time, gold is selling for $426.60 per troy ounce, and 1.0000 troy ounce equals 31.1035 g. How tall would your million-dollar cube be?

Solution 4E First we have to find the mass of the gold that has a value of one million dollar (1$ 6 × 10 ). Then using the value of density of gold one can find the volume of this mass of gold. The 3 volume V of the cube is related to the length of one side by V = L . Step 1 of 3: 1 troy ounce 3 Mass of gold of value one million dollar = (1$ × 10 ) ( $426.60 )( 1 troy ounce 6 31.1035×10 = 10 × ( 426.60 ) = 72.9 kg