A hollow cylindrical copper pipe is 1.50 m long and has an outside diameter of 3.50 cm and an inside diameter of 2.50 cm. How much does it weigh?

Solution 7E Step 1 of 3: 2 V olume of cylinder is , V = R L V olume of hollow cylinder, V = (R R2) 1 Where R is inner diameter 1 R is outer er diameter 2 2 2 V = 3.14[(0.0175 m) (0.0125 m) ] = 7.07 × 10 m4 3 Step 2 of 3: We know that m = V m = V = 8.9 × 10 kg/m × 7.07 × 10 m 4 3 = 6.29 kg