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# You are designing a diving bell to withstand the pressure ISBN: 9780321675460 31

## Solution for problem 14E Chapter 12

University Physics | 13th Edition

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Problem 14E

You are designing a diving bell to withstand the pressure of seawater at a depth of 250 m. (a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.) (b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (Ignore the small variation of pressure over the surface of the window.)

Step-by-Step Solution:

Solution 14E Introduction First we have to calculate the gauge pressure at the given depth. Now using the gauge pressure and the pressure inside the bell, we can calculate the pressure difference. From the pressure difference and are of the window, we can calculate the net force acting on the bell. Step 1 The pressure at height h is given by P = gh Here we have = 1000 kg/m 3 g = 9.8 m/s 2 h = 250 m Hence hence we have 3 2 6 P = (1000 kg/m )(9.8 m/s )(250 m) = 2.35 × 10 Pa 6 Hence the pressure at 250 m depth is 2.35 × 10 Pa.

Step 2 of 2

##### ISBN: 9780321675460

This full solution covers the following key subjects: pressure, depth, Bell, Water, inside. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The answer to “You are designing a diving bell to withstand the pressure of seawater at a depth of 250 m. (a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.) (b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 30.0 cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (Ignore the small variation of pressure over the surface of the window.)” is broken down into a number of easy to follow steps, and 96 words. Since the solution to 14E from 12 chapter was answered, more than 332 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 14E from chapter: 12 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460.

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