×
Get Full Access to University Physics - 13 Edition - Chapter 12 - Problem 40e
Get Full Access to University Physics - 13 Edition - Chapter 12 - Problem 40e

×

# BIO Artery Blockage. A medical technician is trying to

ISBN: 9780321675460 31

## Solution for problem 40E Chapter 12

University Physics | 13th Edition

• Textbook Solutions
• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants

University Physics | 13th Edition

4 5 1 273 Reviews
31
2
Problem 40E

BIO Artery Blockage. A medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is 1.20 X 104 Pa, while in the region of blockage it is 1.15 X 104 Pa. Furthermore, she knows that blood flowing through the normal artery just before the point of blockage is traveling at 30.0 cm/s, and the specific gravity of this patient’s blood is 1.06. What percentage of the cross-sectional area of the patient’s artery is blocked by the plaque?

Step-by-Step Solution:
Step 1 of 3

Solution 40E This question can be solved by combining Bernoulli’s equation and continuity equation. Bernoulli’s principle states that the summation of pressure energy, kinetic energy per unit volume and potential energy per unit volume of a flowing fluid remains constant. 4 Given that, P 1 = 1.20 × 10 Pa v 1 30.0 cm/s = 0.3 m/s P = 1.15 × 10 Pa 2 3 3 Density of blood d blood= 1.06 × 1000 kg/m = 1060 kg/m We need to calculate v . 2 From Bernoulli’s equation, 1 2 1 2 P 1 + 2 blood× v 1 = P 2 + 2 blood× v 2 (Potential energy term is zero as the heart remains at the same height) 1.20 × 10 +4 1 × 1060 × (0.3) = 1.15 × 10 + 4 1 × 1060 × v 2 2 2 2 4 2 0.05 × 10 + 47.7 = 530 × v 2 v 2 1.02 m/s Now, applying continuity equation, we get A v1= 1 v 2 2 A /1 = 2 /v 2 1 A /A = 1.02/0.3 1 2 A /1 = 2.4 A /2 = 1.29 Therefore, 29% of the patient’s artery is open. So, the block percentage is = (100 29)% = 71% Therefore, 71% of the cross-sectional area of the patient’s artery is blocked by the plaque.

Step 2 of 3

Step 3 of 3

#### Related chapters

Unlock Textbook Solution