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Answer: Rank the volume of air in the glass, from greatest

Chapter 14, Problem 1R

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QUESTION:

Problem 1R

Rank the volume of air in the glass, from greatest to least, when it is held

a. near the surface as shown.

b. 1 m beneath the surface.

c. 2 m beneath the surface.

Questions & Answers

QUESTION:

Problem 1R

Rank the volume of air in the glass, from greatest to least, when it is held

a. near the surface as shown.

b. 1 m beneath the surface.

c. 2 m beneath the surface.

ANSWER:

Solution 1R

Introduction

If we go deep inside the liquid, the pressure of the liquid increases with the depth. We will use this information and the ideal gas equation to calculate investigate the change in the volume.

Solution

Step 1

The pressure of the gas increases with the depth of the liquid. So the pressure on the air of the gas will be highest at 2 m beneath the water, at 1 m beneath the water the pressure will be less than 2 m and higher than surface of the water and it will be least at the surface.

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