Solution Found!
Answer: In periods of peak demand, power companies lower
Chapter 23, Problem 10P(choose chapter or problem)
Problem 10P
In periods of peak demand, power companies lower their voltage. This saves them power (and saves you money!). To see the effect, consider a 1200-W coffeemaker that draws 10 A when connected to 120 V. Suppose the voltage is lowered by 10% to 108 V. By how much does the current decrease? By how much does the power decrease? (Caution: The 1200-W label is valid only when 120 V is applied. When the voltage is lowered, it is the resistance of the toaster, not its power, that remains constant.)
Questions & Answers
QUESTION:
Problem 10P
In periods of peak demand, power companies lower their voltage. This saves them power (and saves you money!). To see the effect, consider a 1200-W coffeemaker that draws 10 A when connected to 120 V. Suppose the voltage is lowered by 10% to 108 V. By how much does the current decrease? By how much does the power decrease? (Caution: The 1200-W label is valid only when 120 V is applied. When the voltage is lowered, it is the resistance of the toaster, not its power, that remains constant.)
ANSWER:
Solution 10P
Step 1:
The equation for electric power,
Where, H - Heat produced
t - Time of current flow
I - Amount of current flowing through the circuit
R - resistance offered by the circuit
Ohm’s law states that, V = IR, Where “V” is the voltage in the circuit.