A punter drops a ball from rest vertically 1 meter down onto his foot. The ball leaves the foot with a speed of 18 m/s at an angle 55º above the horizontal. What is the impulse delivered by the foot (magnitude and direction)?

Step-by-step solution In this problem a punter drop a ball from rest vertically so,if the ball leaves the feet with a speed at some angle then what is the impulse deliver by the feet by using the given data respectively: Step 1 of 7 The impulse is defined as the change in momentum of the object caused by a force acted on it for a very small time. Step 2 of 7 The velocity of the ball before it hits the leg is calculated as, Here, u is the initialvelocity of the ball, g is the acceleration due to gravity and s is the displacement of the ball. Substitute 0 m/s for u, 9.8 m/s2 for g and 1 m for s . Hence, the velocity of the ball is 4.427 m/s. Assu me mass m of the ball is 55.0 g ,so the initial momentum of the ball is calculated as, Substitute 55.0 g for m and 4.427 m/s for v . Assume as the unit vector in downward direction. The initial momentum will be in downward direction. So, the initial momentum is . Step 3 of 7 The final momentum is calculated as, Here, is the final velocity of ball. Substitute 18 m/s for and 55.0 g for m.