What is wrong with this "proof" by strong induction

Chapter 5, Problem 29E

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What is wrong with this "proof" by strong induction? "Theorem" For every nonnegative integer n, 5n = 0. Basis Step: 5?0 = 0.Inductive Step: Suppose that 5j = 0 for all nonnegative integers j with 0 ? j ? k. Write k + 1 = i + j. where i and j are natural numbers less than k + 1. By the inductive hypothesis, 5(k + 1) = 5(i + j) = 5i + 5j = 0 + 0 = 0.

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