an ice show, a 60.0-kg skater leaps into the air and is caught by an initially stationary 75.0-kg skater. (a) What is their final velocity assuming negligible friction and that the 60.0-kg skater original horizontal velocity is 4.00 m/s? (b) How much kinetic energy is lost?
Step-by-step solution In this problem we have to calculate the final velocity of the skater during the ice show without considering any friction and also find the loss in kinetic energy by using the given data respectively: Step 1 of 7 (a) For a collision, the momentum will be conserved. So, …… (1) Here is the mass of one skater, is the mass of another skater, is the velocity of first skater before collision, is the velocity of second skater before collision, is the velocity after collision. Step 2 of 7 Substitute in equation (1), Further solve by cross multiplication, Therefore, the final velocity is . Step 3 of 7 (b) The expression of initial kinetic energy is: …… (2) Here m is the mass and is the initial velocity. Step 4 of 7 Substitute (2) and get: Hence, the initial kinetic energy is 480 J.