A sample of 100 resistors has an average resistance of \(50\ \Omega\) and a standard deviation of \(5\ \Omega\). A second sample of 100 resistors has an average resistance of \(100\ \Omega\) and a standard deviation of \(5\ \Omega\). If the two samples are combined, the standard deviation of all 200 resistances will be .
i. less than \(5\ \Omega\)
ii. greater than \(5\ \Omega\)
iii. equal to \(5\ \Omega\)
iv. can’t tell from the information given
(Hint: Don’t do any calculations. Just try to sketch,
very roughly, histograms for each sample separately,
then for the combined sample.)
Equation Transcription:
Text Transcription:
50 ohms
5 ohms
100 ohms
5 ohms
5 ohms
5 ohms
Answer :
Step 1 of 2 :
Given, a sample of 100 resistors are taken, where, average is 50 and standard deviation is 5
.
From another sample of 100 resistors has an average resistance of 100 and a standard deviation of 5
.
if two samples are combined, The claim to suggest one of the standard deviation given below
(i) less than 5
(ii) greater than 5
(iii) equal to 5
(iv) can’t tell from the information given.
