A 3000-kg cannon is mounted so that it can recoil only in the horizontal direction. (a) Calculate its recoil velocity when it fires a 15.0-kg shell at 480 m/s at an angle of 20.0º above the horizontal. (b) What is the kinetic energy of the cannon? This energy is dissipated as heat transfer in shock absorbers that stop its recoil. (c) What happens to the vertical component of momentum that is imparted to the cannon when it is fired?

Step-by-step solution In this problem a cannon is mounted so that it can recoil only in the horizontal direction so, calculate its recoil velocity as per the given condition ,its kinetic energy and explain what cannon is mounted so that it can recoil only in the horizontal direction. Step 1 of 4 (a) There is no initial momentum. So, according to the conservation of momentum, Substitute . Hence, the recoil velocity is s (2) Step 2 of 4 (b) The expression of kinetic energy is: Here, is mass of cannon and is recoil velocity of cannon.