Two identical pucks collide on an air hockey table. One puck was originally at rest. (a) If the incoming puck has a speed of 6.00 m/s and scatters to an angle of 30.0º ,what is the velocity (magnitude and direction) of the second puck? (You may use the result that ?1 ? ?2 = 90º for elastic collisions of objects that have identical masses.) (b) Confirm that the collision is elastic.

Step-by-step solution In this problem two identical pucks are given ,the velocity of first puck is given we have to calculate the velocity of second puck and also confirm that the collision is elastic collision. Step 1 of 7 Conservation of momentum along x -axis is: Here, and are the masses of two identical pucks, are the initial velocity of puck, are the final velocities of two pucks and scattering angles. Conservation of mo mentum along y -axis is: Here, and are the masses of two identical pucks, are the final velocities of two pucks and scattering angles. Step 2 of 7 The expression of initial kinetic energy is: Here, is the mass of identical puck, are the initial velocity of puck. The expression of final kinetic energy is: Here, and are the masses of two identical pucks and are the final velocities of two pucks. Step 3 of 7 (a) The difference between two scattering angle is . Thus, Rearrange the expression for angle, Substitute for , for and for in the above expression of momentum along x -axis and solve, Step 4 of 7 Substitute for , for and for in the above expression of momentum along y -axis and solve,