Solution Found!
The element titanium has five stable occurring isotopes,
Chapter 2, Problem 6E(choose chapter or problem)
The element titanium has five stable occurring isotopes, differing from each other in the number of neutrons an atom contains. If is the number of neutrons in a randomly chosen titanium atom, the probability mass function of is given as follows:
24 |
25 |
26 |
27 |
28 |
|
\(p(x)\) |
a. Find \(\mu_X\).
b. Find \(\sigma_X\).
Equation Transcription:
Text Transcription:
p(x)
mu_X
sigma_X
Questions & Answers
QUESTION:
The element titanium has five stable occurring isotopes, differing from each other in the number of neutrons an atom contains. If is the number of neutrons in a randomly chosen titanium atom, the probability mass function of is given as follows:
24 |
25 |
26 |
27 |
28 |
|
\(p(x)\) |
a. Find \(\mu_X\).
b. Find \(\sigma_X\).
Equation Transcription:
Text Transcription:
p(x)
mu_X
sigma_X
ANSWER:
Solution 6E
Step1 of 3:
We have the element titanium has five stable occurring isotopes, differing from each other in number of neutrons an atom contains.
Let X is the number of neutrons in a randomly chosen titanium atom, the probability mass function is given as follows:
x |
24 |
25 |
26 |
27 |
28 |
P(x) |
0.0825 |
0.0744 |
0.7372 |
0.0541 |