Solution Found!
Refer to Exercise 16. A competing process produces rings
Chapter 2, Problem 17E(choose chapter or problem)
Refer to Exercise 16. A competing process produces rings whose diameters (in centimeters) vary according to the probability density function
\(f(x)= \begin{cases}15\left[1-25(x-10.05)^{2}\right] / 4 & \\ & 9.85<x<10.25 \\ 0 & \text { otherwise }\end{cases}\)
Specifications call for the diameter to be \(10.0 \pm 0.1 \mathrm{~cm}\). Which process is better, this one or the one in Exercise 16? Explain.
Equation Transcription:
Text Transcription:
f(x)={_0 otherwise ^15[1-25(x-10.05)^2]/4 9.85<x<10.25
Questions & Answers
QUESTION:
Refer to Exercise 16. A competing process produces rings whose diameters (in centimeters) vary according to the probability density function
\(f(x)= \begin{cases}15\left[1-25(x-10.05)^{2}\right] / 4 & \\ & 9.85<x<10.25 \\ 0 & \text { otherwise }\end{cases}\)
Specifications call for the diameter to be \(10.0 \pm 0.1 \mathrm{~cm}\). Which process is better, this one or the one in Exercise 16? Explain.
Equation Transcription:
Text Transcription:
f(x)={_0 otherwise ^15[1-25(x-10.05)^2]/4 9.85<x<10.25
ANSWER:
Answer:
Step 1 of 3:
The probability density function is
The probability that the diameter of a randomly chosen piston ring:
Given the diameter to be