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Two batteries, with voltages V1 and V2, are connected in
Chapter 2, Problem 4E(choose chapter or problem)
Two batteries, with voltages \(V_1\) and \(V_2\), are connected in series. The total voltage V is given by \(V=V_1+V_2\). Assume that \(V_1\) has mean 12 V and standard deviation 1 V, and that \(V_2\) has mean 6 V and standard deviation 0.5 V.
a. Find \(\mu_V\).
b. Assuming \(V_1\) and \(V_2\) to be independent, find \(\sigma_V\).
Questions & Answers
QUESTION:
Two batteries, with voltages \(V_1\) and \(V_2\), are connected in series. The total voltage V is given by \(V=V_1+V_2\). Assume that \(V_1\) has mean 12 V and standard deviation 1 V, and that \(V_2\) has mean 6 V and standard deviation 0.5 V.
a. Find \(\mu_V\).
b. Assuming \(V_1\) and \(V_2\) to be independent, find \(\sigma_V\).
ANSWER:Step 1 of 3
Given total voltage V=V1+V2
Here they gave mean and standard deviations of V1 and V2
We need to find the mean and standard deviations of V
Mean of V1 =E(V1)
=12 V
Standard deviation of V1=
= 1 V
Mean of V2 =E(V2)
=6 V
Standard deviation of V2=
= 0.5 V