Solution Found!
Let X and Y be jointly distributed random variables. This
Chapter 2, Problem 29E(choose chapter or problem)
Let X and Y be jointly distributed random variables. This exercise leads you through a proof of the fact that \(-1 \leq \rho_{X, Y} \leq 1\).
a. Express the quantity \(V\left(X-\left(\sigma_{X} / \sigma_{Y}\right) Y\right)\) in terms of \(\sigma_{X}\), \(\sigma_{Y}\), and \(\operatorname{Cov}(X, Y)\).
b. Use the fact that \(V\left(X-\left(\sigma_{X} / \sigma_{Y}\right) Y\right) \geq 0\) and \(\operatorname{Cov}(X, Y)=\rho_{X, Y} \sigma_{X} \sigma_{Y}\) to show that \(\rho_{X, Y} \leq 1\).
c. Repeat parts (a) and (b) using \(V\left(X+\left(\sigma_{X} / \sigma_{Y}\right) Y\right)\) to show that \(\rho_{X, Y} \geq-1\).
Equation Transcription:
Text Transcription:
-1{</=}rho_{X,Y}{</=}1
V(X-(sigma_X/sigma_Y)Y)
sigma_X
sigma_Y
Cov(X,Y)
V(X-(sigma_X/sigma_Y)Y){>/=}0
Cov(X,=rho_{X,Y}sigma_Xsigma_Y
rho_{X,Y}{</=}1
V(X+(sigma_X/sigma_Y)Y)
rho_{X,Y}{>/=}-1
Questions & Answers
QUESTION:
Let X and Y be jointly distributed random variables. This exercise leads you through a proof of the fact that \(-1 \leq \rho_{X, Y} \leq 1\).
a. Express the quantity \(V\left(X-\left(\sigma_{X} / \sigma_{Y}\right) Y\right)\) in terms of \(\sigma_{X}\), \(\sigma_{Y}\), and \(\operatorname{Cov}(X, Y)\).
b. Use the fact that \(V\left(X-\left(\sigma_{X} / \sigma_{Y}\right) Y\right) \geq 0\) and \(\operatorname{Cov}(X, Y)=\rho_{X, Y} \sigma_{X} \sigma_{Y}\) to show that \(\rho_{X, Y} \leq 1\).
c. Repeat parts (a) and (b) using \(V\left(X+\left(\sigma_{X} / \sigma_{Y}\right) Y\right)\) to show that \(\rho_{X, Y} \geq-1\).
Equation Transcription:
Text Transcription:
-1{</=}rho_{X,Y}{</=}1
V(X-(sigma_X/sigma_Y)Y)
sigma_X
sigma_Y
Cov(X,Y)
V(X-(sigma_X/sigma_Y)Y){>/=}0
Cov(X,=rho_{X,Y}sigma_Xsigma_Y
rho_{X,Y}{</=}1
V(X+(sigma_X/sigma_Y)Y)
rho_{X,Y}{>/=}-1
ANSWER:
Step 1 of 4:
It is given that X and Y are two random variables and are jointly distributed.
Also it is known that -11.
Using these we have to prove the others.