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In a lot of 10 components, 2 are sampled at random for

Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi ISBN: 9780073401331 38

Solution for problem 10SE Chapter 2

Statistics for Engineers and Scientists | 4th Edition

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Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi

Statistics for Engineers and Scientists | 4th Edition

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Problem 10SE

In a lot of 10 components, 2 are sampled at random for inspection. Assume that in fact exactly 2 of the 10 components in the lot are defective. Let X be the number of sampled components that are defective.

a. Find P(X = 0).

b. Find P(X = 1).

c. Find P(X = 2).

d. Find the probability mass function of X.

e. Find the mean of X.

f. Find the standard deviation of X.

Step-by-Step Solution:
Step 3 of 5

Solutions:

Step of 1 of 5:

In a lot of 10 components, 2 are sampled at random for inspection. Here exactly 2 of the 10 components in the lot are defective. Let X be the number of defectives. Then we have to find

P(X=0)P(X=1)P(X=2)Probability mass function of X.Mean of XStandard deviation of X

Step 2 of 5:

(a)

    Here it is given that in a lot 10 components exactly two components are defectives. That means the remaining 8 are non-defectives. 2 are sampled at random for inspection. Since X is the number of defectives

P(X=0)= P(randomly selected two components are non - defectives)

         

The total ways to select two non- defective components are = 8C2 

And the total ways to select two components out of 10 components are = 10C2 

Therefore

                P(X=0) =

                 

                            =  

   

                            =  0.6222

Therefore the probability P(X=0) 0.6222 .

(b) We have to find the probability that P(X=1)

    P(X=1) = P(that one of the two selected components is defective and the other one is non-defective.)

         

  The  total number of ways to select one defective item and one non-defective item is

                                               

                                                                                                 = 8C1 2C1 .    

 

 The total ways to select two components out of 10 components are =   10C2 .

Therefore ,

                P(X=1) =

                                     =   16/45      

                            =  0.3555.

Therefore the probability P(X=1) =  0.3555.

Step 3 of 5:

(c)  We have to find the probability that P(X=2)

    P(X=2) = P(that two selected components are defective.)

         

  The  total number of ways to select two defective components are =  2C2.    

 

 The total ways to select two components out of 10 components are =   10C2 .

Therefore ,

                P(X=1) =

                                     =   1/45      

                            =  0.022.

Therefore the probability P(X=2) = 0.022.

Step 4 of 5

Chapter 2, Problem 10SE is Solved
Step 5 of 5

Textbook: Statistics for Engineers and Scientists
Edition: 4
Author: William Navidi
ISBN: 9780073401331

This full solution covers the following key subjects: Find, components, sampled, lot, defective. This expansive textbook survival guide covers 153 chapters, and 2440 solutions. This textbook survival guide was created for the textbook: Statistics for Engineers and Scientists , edition: 4. The full step-by-step solution to problem: 10SE from chapter: 2 was answered by , our top Statistics solution expert on 06/28/17, 11:15AM. Statistics for Engineers and Scientists was written by and is associated to the ISBN: 9780073401331. Since the solution to 10SE from 2 chapter was answered, more than 404 students have viewed the full step-by-step answer. The answer to “In a lot of 10 components, 2 are sampled at random for inspection. Assume that in fact exactly 2 of the 10 components in the lot are defective. Let X be the number of sampled components that are defective.a. Find P(X = 0).________________b. Find P(X = 1).________________c. Find P(X = 2).________________d. Find the probability mass function of X.________________e. Find the mean of X.________________f. Find the standard deviation of X.” is broken down into a number of easy to follow steps, and 69 words.

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