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A steel manufacturer testing a new additive, for
Chapter 2, Problem 19SE(choose chapter or problem)
A steel manufacturer is testing a new additive for manufacturing an alloy of steel. The joint probability mass function of tensile strength (in thousands of pounds/in2) and additive concentration is
a. What are the marginal probability mass functions for X (additive concentration) and Y (tensile
strength)?
b. Are X and Y independent? Explain.
c. Given that a specimen has an additive concentration of 0.04, what is the probability that its strength is 150 or more?
d. Given that a specimen has an additive concentration of 0.08, what is the probability that its tensile strength is greater than 125?
e. A certain application calls for the tensile strength to be 175 or more. What additive concentration should be used to make the probability of meeting this specification the greatest?
Questions & Answers
QUESTION:
A steel manufacturer is testing a new additive for manufacturing an alloy of steel. The joint probability mass function of tensile strength (in thousands of pounds/in2) and additive concentration is
a. What are the marginal probability mass functions for X (additive concentration) and Y (tensile
strength)?
b. Are X and Y independent? Explain.
c. Given that a specimen has an additive concentration of 0.04, what is the probability that its strength is 150 or more?
d. Given that a specimen has an additive concentration of 0.08, what is the probability that its tensile strength is greater than 125?
e. A certain application calls for the tensile strength to be 175 or more. What additive concentration should be used to make the probability of meeting this specification the greatest?
ANSWER:
Answer:
Step1 of 5:
Given data states that a steel manufacturer testing a new additive, for manufacturing an alloy of steel.
The joint probability mass function of tensile strength (y) and additive concentration (x).
|
Tensile strength |
||
Concentration of additive |
100 |
150 |
200 |
0.02 |
0.05 |
0.06 |
0.11 |
0.04 |
0.01 |
0.08 |
0.10 |
0.06 |
0.04 |
0.08 |
0.17 |
0.08 |
0.04 |
0.14 |
0.12 |
Step2 of 5:
a). Here we need to find the marginal probability mass functions for X and Y.
|
Tensile strength (y) |