Solution Found!
The specific gravity of a substance is given by G = DS/DW,
Chapter 3, Problem 9E(choose chapter or problem)
The specific gravity of a substance is given by \(G=D_{S} / D_{W}\), where \(D_{S}\) is the density of the substance in \(\mathrm{~kg} / \mathrm{m}^{3}\) and \(D_{W}\) is the density of water, which is known to be \(1000 \mathrm{~kg} / \mathrm{m}^{3}\). The density of a particular substance is measured to be \(D_{S}=500 \pm 5 \mathrm{~kg} / \mathrm{m}^{3}\). Estimate the specific gravity, and find the uncertainty in the estimate.
Equation Transcription:
Text Transcription:
G=D_S/D_W
D_S
kg/m^3
D_W
1000 kg/m^3
D_S=500{+/-}5kg/m^3
Questions & Answers
QUESTION:
The specific gravity of a substance is given by \(G=D_{S} / D_{W}\), where \(D_{S}\) is the density of the substance in \(\mathrm{~kg} / \mathrm{m}^{3}\) and \(D_{W}\) is the density of water, which is known to be \(1000 \mathrm{~kg} / \mathrm{m}^{3}\). The density of a particular substance is measured to be \(D_{S}=500 \pm 5 \mathrm{~kg} / \mathrm{m}^{3}\). Estimate the specific gravity, and find the uncertainty in the estimate.
Equation Transcription:
Text Transcription:
G=D_S/D_W
D_S
kg/m^3
D_W
1000 kg/m^3
D_S=500{+/-}5kg/m^3
ANSWER:
Answer :
Step 1 of 3:
Given the specific gravity of a substance is given by
Where, is the density of the substance in
D is the density of water, it's to be 1000
The density of a particular substance is measured to be = 500
5