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A 4-kW resistance heater in a water heater runs for 2

Fluid Mechanics | 2nd Edition | ISBN: 9780071284219 | Authors: Yunus A. Cengel, John M. Cimbala ISBN: 9780071284219 39

Solution for problem 32P Chapter 1

Fluid Mechanics | 2nd Edition

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Fluid Mechanics | 2nd Edition | ISBN: 9780071284219 | Authors: Yunus A. Cengel, John M. Cimbala

Fluid Mechanics | 2nd Edition

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Problem 32P

A 4-kW resistance heater in a water heater runs for 2 hours to raise the water temperature to the desired level. Determine the amount of electric energy used in both kWh and kJ.

Step-by-Step Solution:

Solution

Step 1

We know that power is equal to work per unit time

P=

P= Power in watts

W=Work done in joules

t=time

W= P t

Step 2 of 2

Chapter 1, Problem 32P is Solved
Textbook: Fluid Mechanics
Edition: 2
Author: Yunus A. Cengel, John M. Cimbala
ISBN: 9780071284219

Fluid Mechanics was written by and is associated to the ISBN: 9780071284219. The answer to “A 4-kW resistance heater in a water heater runs for 2 hours to raise the water temperature to the desired level. Determine the amount of electric energy used in both kWh and kJ.” is broken down into a number of easy to follow steps, and 33 words. This full solution covers the following key subjects: Water, heater, kwh, determine, electric. This expansive textbook survival guide covers 15 chapters, and 1547 solutions. The full step-by-step solution to problem: 32P from chapter: 1 was answered by , our top Engineering and Tech solution expert on 07/03/17, 04:51AM. Since the solution to 32P from 1 chapter was answered, more than 512 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Fluid Mechanics, edition: 2.

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A 4-kW resistance heater in a water heater runs for 2