An airplane flies horizontally at 55.0 m/s. Its propeller delivers 1500 N of thrust (forward force) to overcome aerodynamic drag (backward force). Using dimensional reasoning and unity conversion ratios, calculate the useful power delivered by the propeller in units of kW and horsepower.

Solution to 40P

Step 1</p>

We need to find the power delivered by the propeller in kW and horsepower units.

We know that

v=velocity of the body

F= force

Step 2</p>

Horizontal velocity of the airplane=55m/s

Forward force=1500N

P=(1500x55)W=82500W

Thus power in kW is 82.5kW