A 5–m–long, 4–m–high tank contains 2.5–m–deep water when not in motion and is open to the atmosphere through a vent in the middle. The tank is now accelerated to the right on a level surface at 2 m/s2. Determine the maximum pressure in the tank relative to the atmospheric pressure.
Step 1 of 4</p>
In the given problem, a tank of length L= 5m and height h=4 m which contains a water to a height of is open to atmosphere through a vent in the middle as shown in the figure below. We need to calculate the maximum pressure in tank relative to atmospheric pressure when the tank is accelerated at to the right on the level surface as shown below,
Step 2 of 4</p>
The density of water is taken as . Also as the acceleration of tank is along horizontal direction(), the vertical components of acceleration will be .
By taking the horizontal direction as x-axis and the vertical upward direction as y-axis, the tangent of the angle the free surface makes with the horizontal surface is given by,
Substituting , and