The friction pawl is pinned at A and rests against the wheel at B. It allows freedom of movement when the wheel is rotating counterclockwise about C. Clockwise rotation is prevented due to friction of the pawl which tends to bind the wheel. If (ms)B = 0.6, determine the design angle u which will prevent clockwise motion for any value of applied moment M. Hint: Neglect the weight of the pawl so that it becomes a two-force member. u M B C 20 A Prob. 829

Notes Taken for EMT on March 28, 2016 First Order System with a Harmonic input Recall, for a step input, we had F(t) = 0 @ t = 0 A F(t) = a 0 @ t > 0 For a Harmonic Input to the 1 order system, we have F(t) = 0 @ t =0 A F(t) = sin(ωt ) for t > 0 a 0 amplitude frequency The solution for harmonic input is A −t x(f) = a0 −1 τ 2 sin[ωt−tan ωt )]+Ce √ 1+(ωt) a 1 again, τ = a0 The Phase Shift is defined as −1 Φ(ω) = tan (ωt) (ϕ is in radians) ϕ(ω) The steady state response lags by time delay ωt = & ω is the frequency of the si