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Locate the centroid x of the | Ch 9 - 9-13, 14th Edition

Engineering Mechanics: Statics | 14th Edition | ISBN: 9780133918922 | Authors: Russell C. Hibbeler ISBN: 9780133918922 126

Solution for problem 9-13 Chapter 9

Engineering Mechanics: Statics | 14th Edition

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Engineering Mechanics: Statics | 14th Edition | ISBN: 9780133918922 | Authors: Russell C. Hibbeler

Engineering Mechanics: Statics | 14th Edition

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Problem 9-13

Locate the centroid x of the area.

Step-by-Step Solution:
Step 1 of 3

OrganicChemistry 2Week 9 Important Information: Professor’s Email: jsal@utep.edu Class Website: organic.utep.edu/courses/2325 Class Code (E-book): utep2325spring2016 Includes examples of the Homework! Posted the week before the homework’s are due to help everyone get 100’s! S5- The pi electrons are 6 for this whole thing. In the first step a NO2 group is added to the benzene ring. When you introduce H2/Pd to a NO2 group the oxygens are replaced with hydrogens. When acetic anhydride is added one hydrogen comes off, and half of the acetic anhydride replaces it. An NO2 group is added again but this happens para to the other nitrogen group. This repeating what happened to other NO2 group, so the oxygens come off and are replaced by hydrogens. Now instead of adding acetic anhydride, cold HCl and NaNO2 are added which turns NH2 into a diazonium compound. MAKE SURE TO HAVE THE CL IN THE PICTURE. The CuOH replaces the diazonium with an OH group. S6 This is a reaction from last semester a carboxylic acid with thionyl chloride takes off the OH group and replaces it with Cl. In this next step the first intermediate is just added onto the benzene ring. In this step a nitrogen-nitrogen compound double bonds to the carbon with oxygen, the oxygen Is removed. The strong base is able to wash away the nitrogens. In this step the ethanoyl group is added para. In this step the double bonded oxygen is converted to an alcohol. The HBr replaces the alcohol group in this step. The addition of Mg removed the Br from the carbon group, if you notice the carbon is charged, the bromine is and so is the Mg. In this step CO2 comes in to satisfy the charged carbon (the Br and Mg are still in the image). If you look closely one of the oxygens is negatively charged. In the final step Mg and Br are washed away and the oxygen negatively charged is protonated.

Step 2 of 3

Chapter 9, Problem 9-13 is Solved
Step 3 of 3

Textbook: Engineering Mechanics: Statics
Edition: 14
Author: Russell C. Hibbeler
ISBN: 9780133918922

The full step-by-step solution to problem: 9-13 from chapter: 9 was answered by , our top Engineering and Tech solution expert on 11/10/17, 05:25PM. Engineering Mechanics: Statics was written by and is associated to the ISBN: 9780133918922. Since the solution to 9-13 from 9 chapter was answered, more than 254 students have viewed the full step-by-step answer. The answer to “Locate the centroid x of the area.” is broken down into a number of easy to follow steps, and 7 words. This textbook survival guide was created for the textbook: Engineering Mechanics: Statics, edition: 14. This full solution covers the following key subjects: area, centroid, locate. This expansive textbook survival guide covers 11 chapters, and 1136 solutions.

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Locate the centroid x of the | Ch 9 - 9-13, 14th Edition