Solution Found!
. The concrete gravity dam is held in place by its own
Chapter 9, Problem 9-122(choose chapter or problem)
The concrete “gravity” dam is held in place by its own weight. If the density of concrete is \(\rho_{c}=2.5 \mathrm{Mg} / \mathrm{m}^{3}\), and water has a density of \(\rho_{w}=1.0 \mathrm{Mg} / \mathrm{m}^{3}\), determine the smallest dimension d that will prevent the dam from overturning about its end A.
Questions & Answers
QUESTION:
The concrete “gravity” dam is held in place by its own weight. If the density of concrete is \(\rho_{c}=2.5 \mathrm{Mg} / \mathrm{m}^{3}\), and water has a density of \(\rho_{w}=1.0 \mathrm{Mg} / \mathrm{m}^{3}\), determine the smallest dimension d that will prevent the dam from overturning about its end A.
ANSWER:
Problem 9-122
. The concrete gravity dam is held in place by its own weight. If the density of concrete is pc = , and water has a density of pw = , determine the smallest dimension d that will prevent the dam from overturning about its end A.
Step by Step Solution
Step 1 of 6
First we will find the minimum value of d so that the dam does not tip over point A due to the water pressure. The density of water is and the density of concrete is pc
All we have to do is to find every external force that acts on the dam and then use the equilibrium condition for the rotation about point A to get the distance d.
Since we are not given the length of the dam we will have to calculate the force on the one slice of the dam F/b