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The number of flaws in a given area of aluminum foil

Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi ISBN: 9780073401331 38

Solution for problem 2E Chapter 4.3

Statistics for Engineers and Scientists | 4th Edition

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Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi

Statistics for Engineers and Scientists | 4th Edition

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Problem 2E

The number of flaws in a given area of aluminum foil follows a Poisson distribution with a mean of 3 per \(\mathrm{m}^{2}\). Let \(X\) represent the number of flaws in a 1 \(\mathrm{m}^{2}\) sample of foil.

a. P(X = 5)

b. P(X = 0)

c. P(X < 2)

d. P(X > 1)

e. \(\mu_{X}\)

f. \(\sigma_{X}\)

Equation Transcription:

Text Transcription:

 

m^2

X

mu_X

sigma_X

Step-by-Step Solution:

Solution

Step 1 of 7

Let X represents the no.of flaws in a sample

Here Xpoisson()

The pmf of Poisson distribution is p(x)=,x=0,1,2,............

Given mean =3

The mean of poisson distribution is

So =3


Step 2 of 7

Chapter 4.3, Problem 2E is Solved
Step 3 of 7

Textbook: Statistics for Engineers and Scientists
Edition: 4
Author: William Navidi
ISBN: 9780073401331

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The number of flaws in a given area of aluminum foil