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Get Full Access to Statistics For Engineers And Scientists - 4 Edition - Chapter 4.3 - Problem 12e
Get Full Access to Statistics For Engineers And Scientists - 4 Edition - Chapter 4.3 - Problem 12e

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# Two-dimensional Poisson process. The number of plants of a

ISBN: 9780073401331 38

## Solution for problem 12E Chapter 4.3

Statistics for Engineers and Scientists | 4th Edition

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Problem 12E

Two-dimensional Poisson process. The number of plants of a certain species in a certain forest has a Poisson distribution with mean 10 plants per acre. The number of plants in $$T$$ acres therefore has a Poisson distribution with mean 10T .

a. What is the probability that there will be exactly 18 plants in a two-acre region?

b. What is the probability that there will be exactly 12 plants in a circle with radius 100 ft? (1 acre = $$43,560\mathrm{\ ft}^2$$.)

c. The number of plants of a different type follows a Poisson distribution with mean $$\lambda$$ plants per acre, where $$\lambda$$ is unknown. A total of 5 plants are counted in a 0.1 acre area. Estimate $$\lambda$$, and find the uncertainty in the estimate.

Equation Transcription:

Text Transcription:

T

43,560 ft^2

lambda

Step-by-Step Solution:

Solution

Step 1 of  3

Here given the no. of plants in forest has a poisson distribution with mean 10 per acre

Let X represents the no. of plants

The pmf of poisson distribution is P(x) =, x=0,1,2,............

Then Xpoisson(10)

a) Here we have to find the probability that there will be exactly 18 plants in 2 acre

For one acre 10 plants

For 2 acre 20 plants

Hence =20

Now P(x=18)=

=0.0844

Hence  the probability that there will be exactly 18 plants in 2 acre is 0.0844

Step 2 of 3

Step 3 of 3

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